1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
|
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <limits.h>
int primerjaj_cela (const void * a, const void * b) {
const int * c = (const int *) a;
const int * d = (const int *) b;
return *d - *c; /* najv proti najm */
}
int main (int argc, char ** argv) {
char * buf = malloc(500);
fgets(buf, 500, stdin);
char * cp;
int N = strtoll(buf, &cp, 10);
cp++;
int M = strtoll(cp, NULL, 10);
int * x = calloc(N+1, sizeof(int));
int * g = malloc((M+1)*sizeof(int));
int * gl = malloc((M+1)*sizeof(int));
for (int o = 0; o < M; o++)
g[o] = INT_MAX;
realloc(buf, (N+1)*6*9);
fgets(buf, (N+1)*6*9, stdin);
cp = buf;
int i = 0;
int mx = 0;
do {
int xi = strtoll(cp, &cp, 10);
// if (xi != 0)
x[++i] = xi;
if (xi > mx)
mx = xi;
cp++;
} while (cp[-1] != 0 && cp[-1] != '\n' && cp[-1] != '\r');
free(buf);
if (N != i) {
fprintf(stderr, "error %d ni %d\n", N, i);
for (int o = 1; o <= i; o++)
fprintf(stderr, " %d\n", x[o]);
}
fprintf(stderr, "max = %d\n", mx);
for (i = 0; i <= mx; i++) {
int s = 0;
for (int j = 1; j <= N; j++)
s += abs(i-x[j]);
int mo = 0;
int me = 0;
for (int o = 0; o < M; o++) {
if (g[o] > mo) {
mo = g[o];
me = o;
}
}
if (mo > s)
g[me] = s;
}
int s = 0;
for (int o = 0; o < M; o++) {
fprintf(stderr, "GOSTILNA %d ima seštevek %d\n", o, g[o]);
s += g[o];
}
fprintf(stdout, "%d\n", s);
return 0;
}
|